Why does ‘$true -eq “string”’ returns $true? [duplicate]
This question already has an answer here:
Why is $false -eq “” true?
In powerShell you compare a boolean with a string with the “-eq” operator it will always return the same boolean as I used to compare.
$shouldBeFalse = $true -eq “hello”
$shouldBeTrue = $false -eq “hello”
The variable $shouldBeFalse is $true.
The variable $shouldBeTrue is $false.
I had to use the “Equals” method:
$shouldBeFalse = $true.Equals(“hello”)
In this case $shouldBeFalse is $false.
But why returns the -eq operator with boolean these kind of results?
PowerShell will always evaluate using the type of the left-side argument. Since you have a boolean on the left PowerShell will try and cast “Hello” as a boolean for the purpose of evaluating with
So in your case
"hello" is converted to a boolean value
[bool]"hello" which would evaluate to True since it is not a zero length string. You would see similar behavior if you did the opposite.
PS C:\> "hello" -eq $true False PS C:\> [bool]"hello" -eq $true True
In the first case
$true is converted to a string “true” which does not equal “hello” hence false. In the second case we cast “hello” to boolean so the
-eq will compare boolean values. For reasons mentioned about this evaluates to True.
Another good explanation comes from this answer which might get your question flagged as a duplicate: Why is $false -eq “” true?
> 0 and
"hello" length > 0 so it is
== 0 and
"hello" length < 0 so it is
When you use Equals, the var are compared as strings, so
$TRUE isn’t equal to
hello -> FALSE.
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